**Q.1.**

Long. 35** ^{o},**36’.5W. is in zone +2.

GMT = 3^{h} 35^{m} 12^{s}

Therefore** **ZT = 3^{h} 35^{m} 12^{s }– 2^{h} = 1^{h} 35^{m} 12^{s}**.**

**Q.2.**

Date = 5 July. ZT = 3^{h} 20^{m} 30^{s}

Long. 145** ^{o} **15’.33E is in zone -10.

Therefore** **GMT = 3^{h} 20^{m} 30^{s }– 10^{h}

Therefore** **GD = 17^{h} 20^{m} 30^{s }, 4 July.

**Q.3.** Long. 158** ^{o},** 2’.38E is in zone -11.

If GD = 2330, 3 July, then ZT = 2330 + 11^{h}

Therefore ZT = 1030 4 July.

**Q.4.**

Long. 179** ^{o},**59’.9E is in zone -12.

Therefore** **ZT = GD + 12^{h}

Therefore** **** **ZT = 30. April 12^{h} 01^{m} + 12^{h }

Therefore ZT = 1 May. 00^{h} 01^{m}

** ****Q.5.**

Long. 179** ^{o},**59’.9W is in zone +12.

Therefore** **ZT = GD – 12^{h}

Therefore** **ZT = 30 April 11^{h} 59^{m }– 12^{h }

Therefore ZT = 29th. April 23^{h} 59^{m}

**Q.6.**

Both ships are positioned on the Equator and are 2 minutes of arc apart in terms of longitude.

Therefore the distance between the ships is 2 x 1855.32 m. = 3710.64 m.

Therefore, although the ships are in dates two days apart, they are only approx. 3.7 geographical miles apart.

Click here to return to exercise 5

** **A fuller explanation of this topic is given in the book ‘Astro Navigation Demystified’.

Useful Link: The Sun as a time keeper.

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